Momentumof `gamma` - ray proton of energy 3 eV in kg-m/s will be

Options

A. `1.6 xx 10^(-19)`
B. `1.6 xx 10^(-21)`
C. `1.6 xx 10^(-24)`
D. `1.6 xx 10^(-27)`

Answer

C

Explanation

Energy of X-ray `= 3 xx 10_(3) eV`
`lamda=(lamda_(C))/(epsilon)=(12400eV A^(@))/(3 xx10^(3)eV)=(12.4)/(3)A^(@)`
momentum `(P) =(lamda)/(lamda)=(lamda xx 3)/(12.4 xx 10^(-10))`
`= 1.6 xx 10_(-24) kg m//s`