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Starting from rest a 10 kg object is act...

Starting from rest a 10 kg object is acted upon by only one force as indicated in figure. Then the total work done by the force in 5 seconds is

A

90 J

B

320 J

C

245 J

D

490 J

Text Solution

Verified by Experts

The correct Answer is:
B
Change in velocity `=("area under F-T graph")/("mass")`
`=(120+(-40))/(10)=8 m//s`
`W_(f)=DeltaK.E = (1)/(2)(10)8_(2) = 320 J`
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