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A pulse of light of duration 100ns is ab...

A pulse of light of duration `100ns` is absorbed completely by a small object initially at rest power of the pulse is `30 mW` and the speed of light is `3 xx 10^(8) ms^(-1)` The final momentum of the object is

A

`0.3 xx 10^(-17) kg ms^(-1)`

B

`1.0 xx 10^(-17) kg ms^(-1)`

C

`3.0 xx 10^(-17) kg ms^(-1)`

D

`9.0 xx 10^(-17) kg ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

Change in momentum
`= ("power" xx "total time")/("speed of time") = (P xx t)/(c)`
`1.0 xx 10_(-17) kg xx m//s`
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