One of the lines in the emission spectrum of `Li^(2+)` has the same wavelength as that of the `2nd` line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is:

Options

A. `n =4 rarr n =2`
B. `n =8 rarr n =2`
C. `n=8 rarr n =4`
D. `n = 12 rarr n =6`

Answer

D

Explanation

For 2nd line of Balmer series in hydorgen specturm
`(1)/(lamda)=R(1)((1)/(2^(2))-(1)/(4^(2)))=(3)/(16)R`
For `Li_(2+) : (Li_(2+))`
which is satisfied by only (D).