In the dimension of a physical quantities are given by `M^(0)L^(1)T^(0)` , then the physical quantity will be

Options

A. pressure if `a=1, b= -1, c= -2`
B. velocity if `a=1, b=0, c= -1`
C. acceleration if `a=1, b=1, c= -2`
D. force if `a=0, b= -1, c= -2`

Answer

A

Explanation

(i) Dimension of velocity `= [M_(0)L_(1)T_(-1)]`
Here , `a=0,b=1,c=-1`
(ii) Dimensions of acceleration
`= [M_(0)L_(1)T_(-2)]`
Here `a = 0,b =1,c= -2`
(iii) Dimensions of forcwe `-[M_(1)L_(1)T_(-2)]`
Here, `a = 1,b=1,T = -2`
(iv) Dimensions of pressure `=[M_(1)L_(-1)T_(-2)]`
`:.` Here, `a = 1,b = -1,c=-2`
`:.` The physical quantity is pressure.