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The time taken by a particle performing ...

The time taken by a particle performing `SHM` on a straight line to pass from point `A` to `B` where its velocities are same is `2` seconds .After another `2` seconds it return to `B` The time period of oscillation is (in seconds)

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
From the given information it can be inferred that points A and B are equidistant from mean position
Hence from diagram it is clear that time period of oscillation is `= 2 + 2 xx 2 + 2 = 8` second.
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