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In the decay Cu^64 rarr Ni^64 + e^+ + v,...

In the decay `Cu^64 rarr Ni^64 + e^+ + v`,
the maximum kinetic energy carried by the netrino which was emitted together with a positron of kinetic energy 0.150 meV? (a) what is the energy of the neutrino which was emitted togather with a positron of kinetic energy 0.150 MeV ? .(b)What is the momentum of this neutrino in kg m `s^(-1)`?Use the formula applicable to photon.

Text Solution

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The correct Answer is:
A, B, C

(a) `KE` of `upsilon + KE` of e = Maximum energy of `e+`
`rArr KE` of `upsilon = (0.680 - 0.180)Mev`
`= 500 Kev`
(b) `p=(E)/(C)=(500 xx10^(3)xx1.6 xx10^(-10))/(3 xx 10^(8))Kg-m//s`
`=2.67 xx 10_(-22) Kg-m//s`.
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