A trolley is being up an incline plane by a man inside the trolley He applied a force of 500 N. If the mass of the man is 50 kg and trolley is 150 kg, then the acceleration of the trolley will be : (`g = 10 m//s^(2)`)

Options

A. `5 m//s^(2)`
B. `1 m//s^(2)`
C. `1.5 m//s^(2)`
D. `2.5 m//s^(2)`

Answer

D

Explanation

`3T - 200 xx 10 xx (1)/(2) =200a`
`3 xx 500 -1000 = 200a`
`a = 2.5 m//s_(2)`