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A block A is kept on a rough inclined pl...

A block A is kept on a rough inclined plane. Initially `theta = 0`. The co-efficient of kinetic friction between A and the inclined plane is `sqrt(3)` The angle `theta` is increased slowly. When `theta` becomes `60^(@)`, then :

A

A slides down with constant velocity

B

A does not slide

C

A slides down with constant non-zero acceleration

D

A slides down with constant acceleration

Text Solution

Verified by Experts

The correct Answer is:
B
At `theta = 60^(@)`
`mg sin theta = mu mg cos theta`

`:.` Net force on the block is zero. Since initially block was at rest relative to inclined plane, it continues to remain in rest.
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RESONANCE-DAILY PRACTICE PROBLEM-DPP No.29
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