In the above question, the velocity of the image of `Q` in plane mirror of block `P` with respect to ground when `Q` is at the lowest point first time is:

Options

A. `sqrt((2mg^(2))/(K))`
B. `sqrt((4mg^(2))/(K))`
C. `sqrt((3mg^(2))/(K))`
D. 0

Answer

D

Explanation

At `t = (T_(Q))/(2)` both the blocks are at extreme position and their velocity is zero
`:. V_(P) = V_(Q) =0`