An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to:

Options

A. `1.25 xx 10^(-28) C-m`
B. `2.0 xx 10^(-25) C-m`
C. `2.5 xx 10^(-28) C-m`
D. `5.0 xx 10^(-28) C-m`

Answer

A

Explanation

`vec(tau)=vec(p)xxvec(E)`
`tau_(max) =pE`
`rArr 50 xx 10^(-28)=p.40`
`rArr p=1.25 xx 10^(-28) C-m`