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Four point masses each of mass m are pla...

Four point masses each of mass m are placed on vertices of a regular tetrahedron. Distance between any two masses is `r`.

A

Gravitation field at centre at zero

B

Gravitation potential at centre is `(-4 Gm)/(r)`

C

Gravitation potential energy of system in `(-6 Gm^(2))/(r)`

D

Gravitation force on one of the point mass is `(sqrt(6) Gm^(2))/(r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

`E_(g) = 0` By symmetry
Potential energy of system `= (-6 Gm^(2))/(r)`
Force between two masses `F= (Gm^(2))/(r^(2)`
Angle between any two force is `60^(@)`
`vec(F)=vec(F)_(1)+vec(F)_(2)+vec(F)_(3)`
`F_("net")^(2)=F_(1)^(2)+F_(2)^(2)+F_(2)^(2)+2 vec(F)_(1).vec(F)_(2)+2 vec(F)_(2).vec(F)_(3)+2vec(F)_(3).vec(F)_(1)`
`F_("net")^(2)=3F^(2)+3F^(2)`
`F_("net")=sqrt(6)F`
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