Figure shows variation of acceleration due to gravity with distance from centre of a uniform spherical planet, Radius of planet is R. What is `r_(1) - r_(1)`

Options

A. `(R)/(4)`
B. `(7R)/(4)`
C. `(4R)/(3)`
D. `2 R`

Answer

B

Explanation

Inside planet
`(9_(0))/(4)g_(0)(1-(d)/(R))rArr d=(3R)/(4)`
Outside planet
`g = g_(0)(R^(2))/((r+h)^(2))rArr h=R` .