A particle of mass `m` is fixed to one end of a massless spring of spring constant `k` and natural length `l_(0)`. The system is rotated about the other end of the spring with an angular velocity `omega` ub gravity-free space. The final length of spring is

Options

A. `m omega^(2) l)/(k)`
B. `(m omega^(2) l)/(k-m omega^(2))`
C. `(m omega^(2) l)/(k + m omega^(2))`
D. none of these

Answer

B

Explanation

`kx=momega^(2)l +momega^(2)x`
`(K-m omega^(2))x=m omega^(2)l rArr x = (m omega^(2)l)/(K-m omega^(2))`