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A body moves in a circular orbit of radi...

A body moves in a circular orbit of radius R under the action of a central force. Potential due to the central force is given by V(r) = kr (k is a positive constant). Period of revolution of the body is proportional to-

A

`R^(1//2)`

B

`R^(-1//2)`

C

`R^(-3//2)`

D

`R^(-5//2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`V (r) kr`
`U (r) = mkr" "omega^(2) = (k)/(r)`
`F = -(dU)/(dr) = -m" "omega = sqrt((k)/(r))`
`T = (2pi sqrt(r))/(sqrt(k))`
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