The binding energy per nucleon of `._(5)B^(10)` is 8 MeV and that of `._(5)B^(11)` is 7.5 MeV. The energy required to remove a neutron from `._(5)B^(11)` is (mass of electron and proton are `9.11 xx 10^(-21) kg` and `1.67 xx 10^(-27) kg` respectively.

Options

A. `2.5 MeV`
B. `8.0 MeV`
C. `0.5 MeV`
D. `7.5 MeV`

Answer

A

Explanation

`10 xx 8 = 80`
`11 xx 7.5 = 82.5`
Energy required `= 82.5 -80 = 2.5`