What are the charges stored in the `1 mu F` and `2 mu F` capacitors in the circuit below, once the currents becomes steady ?

Options

A. `8 mu C` and `4 mu C` respectively
B. `4 mu C` and `8 muC` respectively
C. `3 mu C` and `6 muC` respectively
D. `6 muC` and `3 muC` respectively

Answer

B

Explanation

At steady state capacitor will behave as open circuit

so charge store in `1 mu F = 1 xx 4 = 4 muC`
in `2 muF = 2 xx 4 = 8 muC`