Home
Class 12
PHYSICS
A block is attached with an ideal spring...

A block is attached with an ideal spring and string, and is in equilibrkum as shown in Figure. The acceleration of the block just after breaking the string is `a_(1)` and just after breaking the spring is `a_(2)`. Then

A

`a_(1) = (5g)/(8)`

B

`a_(2) - (3g)/(5)`

C

`a_(1) = (g)/(2)`

D

`a_(2)=g`

Text Solution

Verified by Experts

The correct Answer is:
A, B

`Kx sin 53^(@) + T sin 53^(@) =mg`
`Kx=T 2Kx (4)/(5)mg Kx =(5)/(8)mg`

If string break `a_(1) = (5 mg//8)/(m) = 5g//8`
If spring break, `a_(2)=g cos 53^(@)=3 g//5`
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.51|20 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.52|9 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.49|20 Videos
  • CURRENT ELECTRICITY

    RESONANCE|Exercise High Level Problems (HIP)|21 Videos
  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

The block shown in the figure in is equilibrium. Find acceleration of the block just after the string burns.

Two blocks A and B of same mass m attached with a light string are suspended by a spring as shown in fig. Find the acceleration of block A and B just after the string is cut.

Two blocks A and B of same mass m attached with a light spring are suspended by a string as shown in fig. Find the acceleration of block A and B just after the string is cut.

Two block of mass 4 kg and 5 kg attached a light spring are suspended by a string as shown in figure. Find acceleration of block 5 kg and 4 kg just after the string is cut.

A block tied between identical springs is in equilirium. If upper spring is cut, then the acceleration of the nlock just after cut is 5 ms^(1) Now if instead of upper string lower spring is cut, then the acceleration of the block just after the cut will be (Take g=10 m//s^(2) ).

A block tied between two identical springs is in equilibrium. If upper spring is cut then the acceleration of the block just after cut is 6m//s^(2) downwards. Now, if instead of upper spring, lower spring is being cut then the acceleration of the block just after the cut will be.

Consider a system of two massless idealsprings and a block which is in equilibrium. The acceleration of block just after cutting the right spring is (Take g = 10 m//s^(2) ):

The system shown in the Fig. is in equilibrium. Find the initial acceleration of A, B and C just after the spring 2 is cut.

A uniform rod of mass m length l is attached to smooth hinge at end A and to a string at end B as shown in figure. It is at rest. The angular acceleration of the rod just after the string is cut is :

A block is placed on inclined plane with two strings attached to it as shown in figure. Then calculate frequency of block for small displacement.