In the circuit arrangement shown in figure capacitor is initially unchanged At t = 0 switch is thrown to position '1' it remains closed till the current in the circuit becomes 50 % of maximum current then. Suddenly switch is shifted to position '2' (Assume all batteries are ideal)

Which of the following is the correct options after switch is shifted to position '2'.

Options

A. Energy stored in the capacitor first increases then decreases
B. Energy stored in the capacitor first decreases then increases
C. Energy stored in the capacitor continuously decreases
D. Energy stored in the capacitor continuously increases.

Answer

B

Explanation

When switch is thrown from position 1 to position 2

Total charge flown by battery
`Delta q=2C epsilon-(-Cepsilon//2)=(5C epsilon)/(2)`
Work done by battery `=(5 C epsilon)/(2)xx2 epsilon=5C epsilon^(2)`
Since initially (t = 0) charge on capacitor is `C epsilon//2` it becomes zero after some time and finally becomes `2 C epsilon` so energy first decreases then increases.