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A point moves in the plane so that its t...

A point moves in the plane so that its tangential acceleration `w_tau=a`, and its normal acceleration `w_n=bt^4`, where a and b are positive constants, and t is time. At the moment `t=0` the point was at rest. Find how the curvature radius R of the point's trajectory and the total acceleration w depend on the distance covered s.

Text Solution

Verified by Experts

The correct Answer is:
`R = (a^(3))/(2bs),omega =a sqrt(1-((4bs^(2))/(a^(3)))^(2))]`
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