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A polaroid is placed at `45^@` to an incoming light of intensity `I_0`. Now the intensity of light passing through polaroid after polarisation would be

A

`I_(0)`

B

`I_(0)//2`

C

`I_(0)//4`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`I=I_(0) cos^(2)theta = I_(0)cos^(2)45 = (I_(0))/(2)`
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