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In the figure given below, the position ...

In the figure given below, the position time graph of a particle of mass 0.1kg is shown. The impulse at t=2 sec is

A

`0.2 kg ms^(-1)`

B

`-0.2 kg m s^(-1)`

C

`0.1 kg m s^(-1)`

D

`-0.4 kg m s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

Impulse `=` change in momentum `= 0.1 xx 2 = 0.2 kg ms^(1)`
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