A spherical drop of water as `1mm` radius. If the surface tension of the the water is `50xx10^-3(N)/(m)`, then the difference of pressure between inside and outside the spherical drop is:

Options

A. `25 N//m^(2)`
B. `1000 N//m^(2)`
C. `100 N//m^(2)`
D. `50 N//m^(2)`

Answer

C

Explanation

`P_("excess") = (2T)/(R ) = (2(50 xx 10^(-3)))/((10^(-3))) = 100 N//m^(2)`