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A particle is performing SHM along x-axi...

A particle is performing SHM along x-axis such that its acceleration along x-axis is : `a = 2 -x` where a is in `m//s^(2)` and x is in meter. If speed of the particle at x = 1 is zero in INCORRECT statement is :

A

time period of oscillation is `pi` second

B

amplitude of oscillation is 1 m

C

speed of the particle at `x = 2.5 m` is `(sqrt(3))/(2)` m/s

D

speed of particle at x = 3 m is zero

Text Solution

Verified by Experts

The correct Answer is:
A

`a = - [ x - 2]`
mean position `x = 2`, left extreme `x = 1`, right extreme `x = 3`
amplitude `x = 1`
`omega = 1`
`v_("max") = 1, v = omega sqrt(A^(2) - x^(2)) = 1 sqrt(1 - (1)/(2)) = (sqrt3)/(2)`
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