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A particle of charge per unit mass alpha...

A particle of charge per unit mass `alpha` is released from origin with a velocity `vecv=v_(0)hati` uniform magnetic field `vecB=-B_(0)hatk`. If the particle passes through `(0,y,0)`, then `y` is equal to

A

`-(2v_(0))/(B_(0)alpha)`

B

`(v_(0))/(B_(0)alpha)`

C

`(2v_(0))/(B_(0)alpha)`

D

`-(v_(0))/(B_(0)alpha)`

Text Solution

Verified by Experts

The correct Answer is:
C
Directin of force along `+y` direction so partical passes throught the `+y` axis at a
`y = 2r = (2mv)/(rhoB) = (2 v_(0))/(B_(0) alpha)`
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