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A 1m long wire having tension of 100 N a...

A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :

A

125 Hz

B

150 Hz

C

300 Hz

D

275 Hz

Text Solution

Verified by Experts

The correct Answer is:
A
Length of BC to AC is `(20)/(80)=(1)/(4)`
So, value of loops in BC to AC will also be `1 : 4`
`f_(1)=(1)/(4(0.2))sqrt((T)/(mu))=125 Hz`
`f_(2) = (3)/(4(0.2))sqrt((T)/(mu))=275 Hz`.
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