A radioactive nucleus is being produced ...

A radioactive nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lamda`. If `N_0` are the number of nuclei at time `t = 0`, then maximum number of nuclei possible are.

`(alpha)/(lamda)`

`N_(0)+(alpha)/(lamda)`

`N_(0)`

`(lamda)/(alpha) +N_(0)`

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The correct Answer is:

Maximum number of nuclei will be persent when rate of decay = rate of formation
`rArr lamda N = alpha rArr N=(alpha)/(lamda)`

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