A solid cylinder of mass `M` and radius `R` rolls without slipping down an inclined plane of length `L` and height `h`. What is the speed of its center of mass when the cylinder reaches its bottom

Options

A. `sqrt((3)/(4))gh`
B. `sqrt((4)/(3)gh)`
C. `sqrt(4gh)`
D. `sqrt(2gh)`

Answer

B

Explanation

`Mgh = (1)/(2) I omega^(2)+(1)/(2)mv^(2)`
`Mgh = (1)/(2)xx(3)/(2)mv^(2)rArr v=sqrt((4)/(3)gh)`