An ideal gas undergoes a cyclic process abcda which is shown by pressure-density curve,

Options

A. Work done by the gas in the process 'bc' is zero
B. Work done by the gas in the process 'cd' is negative
C. Internal energy of the has at point 'a' is greater than at state 'c'
D. Net work done by the gas in the cycle is negative.

Answer

A, B, D

Explanation

`rho = (rho)/(M_(0))RT rArr (P)/(rho)=(R)/(M_(0))T`
Slope of curve `alpha` Temperature
Hence cd and ab are isothermal processes
`rho prop (1)/(V)`
i.e bc and da are constant volume process (A) and (B) are true
temp in cd process is greater than ab.
Net work done by the gas in the cycle is negative, as is clear by the PV- diagram.