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A weight mg is suspended from the middle...

A weight mg is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. Find the minimum tenstion required to completely straighten the rope.

Text Solution

Verified by Experts

From the diagram

`27sintheta=mgrArrT=(mg)/(2sin theta)`
The rope will be straight when `theta=0^(@)`
`T=(mg)/(2 sin 0^(@))=prop`
The tension required to completely straighten the rope is infinity.
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