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If sinA=3/5 and cosB=9/41, 0 < A < pi/2 ...

If `sinA=3/5` and `cosB=9/41, 0 < A < pi/2` and `0 < B < pi/2` then find the values of `(i) sin(A+B) (ii) sin(A-B) (iii) cos(A+B) (iv) cos(A-B)`

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To solve the problem, we will follow these steps: ### Step 1: Find cos A Given that \( \sin A = \frac{3}{5} \), we can use the Pythagorean identity: \[ \sin^2 A + \cos^2 A = 1 \] Substituting the value of \( \sin A \): ...
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