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If sinA=1/2,cosB=(12)/(13), w h e r e pi...

If `sinA=1/2,cosB=(12)/(13), w h e r e pi/2ltaltpia` n="" d(3pi)="" `2ltblt2pi`="" ,="" find="" `tan(a-b)dot`<="" b="">

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Given,`sinA=1/2,cosB=(12)/(13)`
Now By solving for tan A we get `tan A=-1/sqrt(3)`
and `tanB=-5/12`
`tan(A-B)=(tanA+tanB)/(1-tanAtanB)`
=`(-1/sqrt(3)-5/12)/(1-(-1/sqrt(3))(-5/12))`
=`(5sqrt(3)-12)/(5+12sqrt(3))`
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