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If sinA=1/2,cosB=(sqrt(3))/2,\ w h e r e...

If `sinA=1/2,cosB=(sqrt(3))/2,\ w h e r e\ pi/2

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Given,`sinA=1/2,cosB=(sqrt(3))/2`
We know that `sin^2A+cos^2A=1`
Then,`cosA=-sqrt(3)/2`
`sinB=1/2`
`tan (A +B) = (tan A -tan B)/(1 +tan A tan B)`
= `((-1/sqrt(3)) - (1/sqrt(3)))/(1 +(-1/sqrt(3)) × (1/sqrt(3))) `
=` (-2/sqrt(3))/(1 – 1/3) `
...
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