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Prove that: sin(60^0-theta)-cos(30^0+the...

Prove that: `sin(60^0-theta)-cos(30^0+theta)=0.`

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We know that`,sin(60^o +theta)−cos(30^o−theta)`
=`cos[90^o−(60^o +theta)]−cos(30^o−theta)`
=`cos(30^o−theta)−cos(30^o−theta)`
...
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Knowledge Check

  • Find the value of sin(60+ theta )-cos(30-theta)

    A
    (A) 0
    B
    (B) 1
    C
    (C) `1/2`
    D
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