If `tan A= xtanB` then prove that `sin(A-B)/sin(A+B)=(x-1)/(x+1)`

Explanation

To prove that \(\frac{\sin(A-B)}{\sin(A+B)} = \frac{x-1}{x+1}\) given that \(\tan A = x \tan B\), we will follow these steps:

### Step 1: Start with the given relationship
We know that:
\[ \tan A = x \tan B \]

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