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If t a nalpha=x+1,tanbeta=x-1, show that...

If `t a nalpha=x+1,tanbeta=x-1,` show that `2cot(alpha-beta)=x^2dot`

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Given,
`tanalpha=x+1 and tanbeta=x−1.`
So,
`2cot(alpha−beta)`
`=2/(tan(alpha−beta))`
`=2((1+tanalphatanbeta)/(tanalpha−tanbeta))`
...
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