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tan20^@+tan40^@+sqrt3 tan20^@ tan40^@= a...

`tan20^@+tan40^@+sqrt3 tan20^@ tan40^@=` `a.sqrt3/4, b. sqrt3/2, c. sqrt3, d. 1`

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To solve the problem \( \tan 20^\circ + \tan 40^\circ + \sqrt{3} \tan 20^\circ \tan 40^\circ \), we can use the identity for the tangent of a sum of angles. ### Step-by-Step Solution: 1. **Recognize the Sum of Angles**: We know that \( \tan(60^\circ) = \tan(40^\circ + 20^\circ) \). 2. **Apply the Tangent Addition Formula**: ...
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tan20^(@)+tan40^(@)+sqrt(3)tan20^(@).tan40^(@)=?

tan20^(@)-tan80^(@)+sqrt(3)tan20^(@)tan80^(@)=

tan 20^(@) + tan40^(@) + sqrt(3).tan 20^(@).tan 40^(@)=

tan40^(@)+tan80^(@)-sqrt(3)tan40^(@)tan80^(@)=

tan20^(@)-tan80^(@)+sqrt(3)=

Solve tan x+tan 2x + sqrt3 tan x tan 2x= sqrt3

Assertion (A) tan20^(@)+tan40^(@)+sqrt(3)tan20^(@)tan40^(@)=sqrt(3)Rason(R):If tan(A+B)=k, then tan A+tan B+k tan A tan B=0

tan x+tan2x+sqrt(3)tan x*tan2x=sqrt(3)

RD SHARMA-TRIGONOMETRIC RATIOS OF COMPOUND ANGLES-Solved Examples And Exercises
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