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(cos 10^0+sin 10^0)/(cos 10^0-sin 10^0) ...

`(cos 10^0+sin 10^0)/(cos 10^0-sin 10^0)` is equal to `tan55^0` b. `cos 55^0` c.`-tan35^0` d. `-cot35^0`

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`LHS = ( Cos 10^@ + Sin 10^@ ) / ( Cos 10^@ - Sin 10^@)`

{ Multiply numerator and and denominator with 1 / Cos 10^@ }

=` [ 1 /Cos 10^@ ( Cos 10^@ + Sin 10^@ ) ] / [ 1/Cos 10^@ ( Cos 10^@ - Sin 10^@ ) ]`

=` [ Cos10^@ / Cos10^@ + Sin10^@ / Cos10^@ ] / [ Cos10^@ / Cos10^@ - Sin10^@ / Cos10^@ ]`

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