The maximum value of `sin^2(120^0+theta)+sin^2(120^0-theta)` is `1//2` b. 3/2 c. `1//4` d. `3//4`

Explanation

To find the maximum value of \( \sin^2(120^\circ + \theta) + \sin^2(120^\circ - \theta) \), we can follow these steps:

### Step 1: Use the sine addition and subtraction formulas
We know that:
\[ \sin(A + B) = \sin A \cos B + \cos A \sin B \]
\[
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