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If cos(A-B)=3/5a n d\ t a n AtanB=2, t h...

If `cos(A-B)=3/5a n d\ t a n AtanB=2, t h e n` `cos A\ cosB=1/5` b. `cosA\ cos B=\ -1/5` c. `sin A\ sin B=\ -1/5` d. `sin A\ sin B=\ -1/5`

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Given,

`cos(A – B) = 3/5`….(i)

`tan A tan B = 2`

`(sin A/cos A) . (sin B/cos B) = 2/1`
...
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