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If tanalpha=x/(x+1)\ and tanbeta=1/(2x+1...

If `tanalpha=x/(x+1)\ and tanbeta=1/(2x+1),\ t h e n\ alpha+beta` is equal to `pi/2` b. `pi/3` c. `pi/6` d. `pi/4`

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Put `x=1`
`tan alpha = 1/2`
`tan beta = 1/3`
`tan(alpha + beta ) = (tan alpha + tan beta)/ (1- tan alpha tan beta)`
...
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