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Prove that: sin38^0+sin 22^0=sin 82^0...

Prove that: `sin38^0+sin 22^0=sin 82^0`

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To proof: `sin(38^o)+sin(22^o)=sin(82^o)`
Let L.H.S=`sin(38^o)+sin(22^o)=sin(82^o)`
As we know the formula `sinA+sinB=2(sin(A+B)/2)(cos(A-B)/2)`
So, L.H.S`=2sin(30^o).cos(8^o)`
L.H.S=`2×(1/2)cos(90^o−8^o)`
L.H.S=` sin82^o`
L.H.S=R.H.S
Hence, `sin(38^o)+sin (22^o)=sin 82^o` is proved.
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