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If `(cosalpha+cosbeta)^2+(sinalpha+sinbeta)^2=lambdacos^2((alpha-beta)/2),` write the value of `lambdadot`

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To find the value of \(\lambda\) in the equation \[ (\cos \alpha + \cos \beta)^2 + (\sin \alpha + \sin \beta)^2 = \lambda \cos^2\left(\frac{\alpha - \beta}{2}\right), \] we can start by simplifying the left-hand side. ...
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