If `sin47^0+sin 61^0-sin 11^0-sin 25^0` is equal to `adot\ sin36^0` b. `cos36^0` c. `cos7^0` d. `cos7^0`

Explanation

`sin 47° + sin 61° – sin 11° – sin 25°`



`= (sin 47° – sin 25°) + (sin 61° – sin 11°)`



Using the formula `sin x – sin y = 2 sin(x – y)/2 cos(x + y)/2,`



`= 2 sin 11° cos 36° + 2 sin 25° cos 36°`



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