Solve the following equation: `2sin^2x+sqrt(3)cos x+1=0`

Explanation

Let us start changing `sin^2x` into `1−cos^2x;` we get
`2(1−cos^2x)+sqrt(3)
​cosx+1=0`

or `2cos^2x−sqrt(3)
​cosx−3=0`

∴`cosx=
​​sqrt(3)
​ or −sqrt(3)/2`

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