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First term of a sequence is 1 and (n+1)t...

First term of a sequence is 1 and `(n+1)th` term is obtained by adding (n+1) to the nth. Find the sequence upto `6th` term.

Text Solution

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first term `=1`
Consider, `{n}=1 therefore({n}+1)^{ {th }}` term
`(1+1)^{ {th }} 2^{ {nd }} { term }=(1)^{ {th }} { term }+(1+1) `
`=1+2 `
...
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