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The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms.

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Let `a, a+d, a+2d, a+3d` are the terms in AP.
Given `a = 11`
Sum of the first four terms of an A.P `= 56`
`a+ a+d+ a+2d+ a+3d = 56`
`4a+6d = 56`
`44+6d = 56`
`6d = 12`
`d = 2` ...
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