The sum of the first `p , q , r` terms of an A.P. are `a , b , c` respectively. Show that `a/p(q-r)+b/q(r-p)+c/r(p-q)=0`

Explanation

We know that `{S}_{{n}}=frac{{n}}{2}[2 {a}+({n}-1) {d}]`
Sum of first `p` terms `=a Rightarrow S_{p}=a`


`Rightarrow frac{P}{2}[2 {a}_{1}+({P}-1) {d}]={a} ldots(1)`


where `a_{1}` is the first term
Sum of first `q` terms `=b=Rightarrow S_{q}=b`


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