If the sums of `n` terms of two arithmetic progressions are in the ratio`\ 2n+5:3n+4,` then write the ratio of their `m t h` term.

Explanation

Let nth term of first A.P. be denoted by `a_n`

And nth term of second A.P. be denoted by `a_n`'

`a_m/(a_m)^'=(a+(m-1)d)/(a'+(m-1)d')`


Now, multiplying both sides by 2 we get,

=`(2a_m)/(2a_m)^'=(2a+2(m-1)d)/(2a'+2(m-1)d')`

=`a_m/(a_m)^'=(2a+(2m-1-1)d)/(2a'+(2m-1-1)d')`

=`[(2m-1)/2.a_m]/[(2m-1)/2.a_m']=[(2m-1)/2(2a+(2m-1-1)d)]/[(2m-1)/2(2a'+(2m-1-1)d')]`

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