Find the `9^(th)` term and the general term of the progressions: `1/4, -1/2 , 1 , -2`

Explanation

the 9th term will be,


`a_9​=ar^(9−1)=ar^8=1/4​(−2)^8=64`


and the general term will be,


`a_n​=ar^(n−1)=1/4​(−2)^(n−1)=(−1)^(n−1)×2^(n−3)`